Thread
profile picture
Virza Azzahra
Student XII IPS
3. Nilai minimum fungsi f(x) = 8 + 2Cosx untuk interval 0 < x < 211
3 tahun yang lalu
total answer
1
total comment
0
share
Terjawab

Jawaban (1)
0
profile picture
Putra Gema Nusa
Rockstar Teacher GURU SMA
1 f(x) = 8 + 2 COS X 8+2 X f'(x) Cheng 이 그 = =-2 sinx 0 O = -2 SINX 0 = sinx = Sin 0 # x=0°tk. 360° > k = 0 -X = 0 o k = x= 360° O EX L2T # Subtituskan x ke f(x) -> X = 0 f(0) = 0 = = 8+2.650 = 8 +2.1 = 10 -> X = 180° f(180°) = 8+ 2.ØS 80° = 8+2.(-1) = 6 =6 -> x= 360 f (360) = 8 +2. Cos 360° = 8+2.1 = 10 sin X X= 5 180° + k. 360° * X >k=0 X= 180° Đ X= {0°, 180°, 360 x° Pahamify 6. Hlai minmum f(x) adalah y = 6 y =
3 tahun yang lalu
total comment
0
Balas
Terverifikasi