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Dian Ayu Larasati
Student •X SMK
Jika diketahui log 2 = 0,3010, log 3 = 0,4771, dan log 5 = 0,6989, maka tentukan nilai dari: a. log 540 b. Log 43,2 C. log 30 125 d. log 6
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Putra Gema Nusa
Rockstar Teacher •GURU SMA
= 3 log 3 + 4 log 2-1 = 3.0,4771 + 4.0,3010 | =1,693 c c. log 130 = log (9.2.3) I + 2 a - U 2 0,6989 +0,3010 +0,4771 il modal: log 2 = 0,3010 log 3 = 0,4771 log 5 =0,6989 a. log 520 = log (10. 3º.2) log 10+ log 33+ log 2 1+ 3 log 3 + log 2 = 1 + 3.0,4771 +0,3010 = 2,7323 b. 432 log 43,2 log = log 932 - log 10 = log (38.29)-1 Dahamify - log 33+ log 27-1 2 こ s 10 0,7385 d. log 128 = log 43 - log (2.3) - 3 logs - (log 2 + log 3) = 3.0,6989 - (0,3010 +0,4771) 2,0904 - 0,7781 = 1,3123 o
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