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Shelma
Student XI IPA
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Muhammad Fauzan Isnanda
Rockstar Teacher GURU SMA
NA MB pers 142 x 2 2 6-X m=20kg substitusi l=6m (1) 440 X = 6NB-600 Ne 880 X = 12 NB-1200 Mis (27 400 X = 3240 - 12 MB W NA =2 MB 1280 X = 2040 x = 2040 / 1280 Torsi di ) B В ujung X = 1,59 Στο lt -l= -Will-F16-x) + MA.l=0 Jadi beban 200. 3 + 440.. = 6 No 6 NA 200-3+ 440.6 -440 X diletakkan 1,59m (1) 440 8= 6MB-600 6 NA = 3240-400X dari 4000 = 3240 - 6 NA (2) 400 x = 3240 - 12 MB Torsi diujung Ir=0 - Pahamify
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